Here are the images of Samsung Galaxy S7 hacked with Ransomware

Just a couple of months ago we have reported about an Android LG Smart TV got its screen bricked after a ransomware infection. Now a series of similar are taking place on the Samsung Galaxy S7 devices, in these attacks the hackers are infecting Galaxy S7 models with some malware, locking out screens and then demanding for ransom payments.

These kind of attacks are currently raising in the UK. The victim, here, told the HackRead website that it happened while they are using Facebook messenger on their own smartphone, and there have not downloaded any app from a third-party nor Google Play Store during the incident or before it. 

This happened on 18th March, when a “penalty notice” from the Enforcement Bailiffs Ltd appeared on this smartphone informing that the victim’s device has been blocked due to the presence some Child abuse content. It should be noted that the Enforcement Bailiffs Ltd is a United Kingdom based commercial property enforcement specialists and they have nothing to do with these cyber crime related cases.

Furthermore, the notice threatened victims in paying 200 GBP or else the so-called offensive material will be made public, and a case will go on trial. Here are the exclusive screenshots provided by the victim:

Moreover, the warning message informed the victim to pay the ransom money through secure online payment platform PaySafeCard.

Since these threats are bullshit from the get go, the only reasonable solution for this ransomware infection is a simple factory reset, once the battery died and that is what the victim did to get back his smartphone successfully. But, in some cases; it is almost impossible to get rid of this ransomware infection. For this, cyber security giants and the Europol have launched a ‘No More Ransom’ Anti-Ransomware Portal which has already decrypted over 2,500 ransomware victims and saved 1.3 Mil Euros from cyber criminals.

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How to use pointer within a Class in C++ Programming

Pointers can be used inside a class for the following reasons:

• Pointers save memory consumed by objects of a class.
• Pointers can be used to allocate memory dynamically i.e., at run time.

Following program demonstrates the use of pointers within a class:

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#include<iostream> using namespace std; class Student { private: string name; string regdno; int age; int *marks; public: string branch; void get_details(); void show_details(); void get_marks(); }; void Student::get_marks() { int n; cout<<“Enter no.of subjects: “; cin>>n; marks = new int[n]; for(int i=0; i<n; i++) { cout<<“Enter subject “<<(i+1)<<” marks: “; cin>>marks[i]; } } int main() { Student s1; s1.get_marks(); return 0; } Input and output for the above program is as follows: Enter no.of subjects: 6 Enter subject 1 marks: 20 Enter subject 2 marks: 15 Enter subject 3 marks: 16 Enter subject 4 marks: 19 Enter subject 5 marks: 20 Enter subject 6 marks: 18

In the above program marks is a pointer inside the class Student. It is used to allocate memory dynamically inside the get_marks() function with the help of new  operator.

Local Classes

A class which is declared inside a function is called a local class. A local class is accessible only within the function it is declared. Following guidelines should be followed while using local classes:

• Local classes can access global variables only along with scope resolution operator.
• Local classes can access static variables declared inside a function.
• Local classes cannot access auto variables declared inside a function.
• Local classes cannot have static variables.
• Member functions must be defined inside the class.
• Private members of the class cannot be accessed by the enclosing function if it is not declared as a friend function.

Below example demonstrates a local class:

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#include<iostream> using namespace std; const float PI = 3.1415; int main() { class Circle { public: int r; void area() { cout<<“Area of circle is: “<<(::PI*r*r); } void set_radius(int radius) { r = radius; } }; Circle c; c.set_radius(10); c.area(); return 0; } Output of the above program is as follows: Area of circle is: 314.15

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